(3x-8)+(4x^2-3x+3)=

Solution for (3x-8)+(4x^2-3x+3)= equation:

Simplifying
(3x + -8) + (4x2 + -3x + 3) = 0

Reorder the terms:
(-8 + 3x) + (4x2 + -3x + 3) = 0

Remove parenthesis around (-8 + 3x)
-8 + 3x + (4x2 + -3x + 3) = 0

Reorder the terms:
-8 + 3x + (3 + -3x + 4x2) = 0

Remove parenthesis around (3 + -3x + 4x2)
-8 + 3x + 3 + -3x + 4x2 = 0

Reorder the terms:
-8 + 3 + 3x + -3x + 4x2 = 0

Combine like terms: -8 + 3 = -5
-5 + 3x + -3x + 4x2 = 0

Combine like terms: 3x + -3x = 0
-5 + 0 + 4x2 = 0
-5 + 4x2 = 0

Solving
-5 + 4x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 4x2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 4x2 = 0 + 5
4x2 = 0 + 5

Combine like terms: 0 + 5 = 5
4x2 = 5

Divide each side by '4'.
x2 = 1.25

Simplifying
x2 = 1.25

Take the square root of each side:
x = {-1.118033989, 1.118033989}